How to skip to a page depends on the selected option condionally?

Hi there! I have a form where we are utilizing the image checkboxes widget. It's great! However, I'm running into some issues when trying to set up conditional logic.

For example, on page 2 there are 3 options in the widget. I want to make it so if someone clicks image 1, they're taken to page 3. If they click option 2, they're redirected to page 8, etc. How can I accomplish this with conditional logic?

Thank you! Here's the form link:

https://form.jotform.com/241008240558147

Hi Andrea,

Thank you for reaching out to Jotform Support.  I’ll need a bit of time to look into this. I’ll get back to you as soon as I can.

Hi Andrea,

Thanks for your patience. After carefully checking, this can be achieved with Skip To/Hide a Page conditional logic, which you already set up. You just need to change the value to the specific option or text that is going to be selected. Entering the text value manually will not work. In order for the condition to work, you have to add a form calculation widget temporarily so that you can copy the exact text or value properly and then paste it into Skip To/Hide a Page conditional logic value. Let me show you how to do it with the cloned version of your form.

1. In form builder, click on Add Form Elements.

2. Then click on Widgets and choose Form Calculation.

3. Next, Click on Add Field on the form calculation widget and select the target field

4. In preview mode, click on each option, copy the text, and save it to your notes so you can just copy and paste it as a conditional logic value.

After you finish copying the texts, you can just delete the form calculation widget from your form. Now, set up the conditional logic again.

5. In form builder, click on Settings.

6, Then click on Add Conditions and select the Skip To/Hide a Page option.

7. And set up the condition similar to what you did before.

Here's the sample result afterwards.

Give it a try and let us know how it goes.